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How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)

User Shane Ray
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\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ √(7)}}\quad ,&{{ -√(2)}})\quad % (c,d) &({{4√(7)}}\quad ,&{{ 5√(2)}}) \end{array}~~~ % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\


\bf d=\sqrt{[4√(7)-√(7)]^2~+~[5√(2)-(-√(2))]^2} \\\\\\ d=\sqrt{(4√(7)-√(7))^2~+~(5√(2)+√(2))^2}\implies d=\sqrt{(3√(7))^2~+~(6√(2))^2} \\\\\\ d=√(3^2\cdot 7~~+~~6^2\cdot 2)\implies d=√(63+72)\implies d=√(135) \\\\\\ \begin{cases} 135=5\cdot 3\cdot 3\cdot 3\\ \qquad 5\cdot 3^2\cdot 3\\ \qquad 15\cdot 3^2 \end{cases}\implies d=√(15\cdot 3^2)\implies d=3√(15)
User HashSu
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