Solve each system by substitution {4p+2q=8 and q=2p+1} {x+6y=2 and 5x+4y=36}

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asked Jun 2, 2018 226k views

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Solve each system by substitution {4p+2q=8 and q=2p+1} {x+6y=2 and 5x+4y=36}

Mathematics
high-school

Dominik Reinert asked

by Dominik Reinert

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1 Answer

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4p +2q = 8
Q=2p+1

4p +2(2p + 1)=8
4p + 4p + 2=8
8p = 6
P=3/4

Substituting p=3/4 into the first equation
4(3/4) +2q =8
3+2q =8
2q=5
Q=5/2

Jacob B answered Jun 6, 2018

by Jacob B

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