Question

Solve each system by substitution {4p+2q=8 and q=2p+1} {x+6y=2 and 5x+4y=36}

Answer 1

4p +2q = 8
Q=2p+1

4p +2(2p + 1)=8
4p + 4p + 2=8
8p = 6
P=3/4

Substituting p=3/4 into the first equation
4(3/4) +2q =8
3+2q =8
2q=5
Q=5/2