Question

How many grams would be contained in 3.49 x 10^80 molecules of H2S04? ( the 80 is an exponent )

Answer 1

`\text{ The mass of H}_2SO_4\text{ is 5.6886 }*\text{ 10}^(58)\text{ grams}`

Step-by-step explanation

Given that;

`\text{ The number of molecules of 3.49 }*\text{ 10}^(80)\text{ }`

Follow the steps below to find the grams of H2SO4

Step 1; Find the number of moles of H2SO4 using the below formula

`\text{ mole }=\text{ }\frac{\text{ Number of molecules}}{\text{ Avgadro's number }}`

Recall, that Avogadro's number is 6.02 x 10^23

`\begin{gathered} \text{ mole = }\frac{\text{ 3.49}*\text{ 10}^(80)}{6.02\text{ }*\text{ 10}^(23)} \\ \\ \text{ mole = }(3.49)/(6.02)*\text{ 10}^{80\text{ - 23}} \\ \text{ mole = 0.58 }*\text{ 10}^(57) \\ \text{ mole = 5.8 }*\text{ 10}^(56)\text{ moles} \end{gathered}`

Step 2; Find the mass of H2SO4 using the formula below

`\begin{gathered} \text{ mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \text{ cross multiply} \\ \text{ mass = mole }*\text{ molar mass} \end{gathered}`

Recall, that the molar mass of 98.079 g/mol

`\begin{gathered} \text{ mass = 5.8 }*\text{ 10}^(56)*\text{ 98.079} \\ \text{ Mass = 5.8 }*\text{ 98.079 }*\text{ 10}^(56) \\ \text{ Mass = 568.86 }*\text{ 10}^(56) \\ \text{ Mass = 5.6886 }*\text{ 10}^(58)\text{ grams} \end{gathered}`