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The heat of combustion of butane , c4h10 , is 2874 kj/mol. what is the heat of combustion of butane, in kj per gram?(provide the right sig. fig)

User Djromero
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the answer will be d i just took the test and got it correct

User Jonathan Parker
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Answer : 49.45 kJ per gram.

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of butane = 2874 kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number
6.023* 10^(23) of particles.

1 mole of
C_4H_(10) weighs = 58.12 g

Thus we can say:

58.12 g of
C_4H_(10) on combustion releases = 2874 kJ

Thus 1 g of
C_4H_(10) on combustion releases =
(2874)/(58.12)* 1=49.45 kJ

Thus the heat of combustion of butane, in kJ per gram is 49.45.

User Sunil Mishra
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