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Sonia has three bracelets. she wears them all at the same time but if a different order each day. how many different combinations does sonia have to choose from
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Mar 22, 2018
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Sonia has three bracelets. she wears them all at the same time but if a different order each day. how many different combinations does sonia have to choose from
Mathematics
high-school
Ubombi
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We can use a factorial to solve this:
3! = 3 * 2 *
1 = 6
So, she can wear them in a total of 6 combos.
Tidylobster
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Mar 28, 2018
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