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The cost of admission to Water World is $7.50. The owner wants to raise the admission cost. For every $1 increase in the admission cost, the number of visitors to the park will drop by 25 per day. Currently, an average of 225 people visit the water park each day. Find the amount by which the admission cost to the water park should be increased to obtain maximum income. 6. The path of the water fro

User Sigal
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Final answer:

To maximize income for Water World, the admission cost should be increased by $0.75, calculated by finding the vertex of the quadratic equation representing the income as a function of price increase and visitor numbers.

Step-by-step explanation:

To find the amount by which the admission cost to Water World should be increased to obtain maximum income, we can create a quadratic equation to represent the income based on the number of visitors and admission cost.

Step 1: Define variables and equation

Let x represent the increase in dollars to the current admission cost of $7.50. The new admission cost would be (7.50 + x) dollars.

With each $1 increase, the number of visitors decreases by 25. The new average number of visitors per day would be (225 - 25x) visitors.

Step 2: Formulate the income

Income, I, is equal to the admission cost multiplied by the number of visitors, which is I = (7.50 + x)(225 - 25x).

Step 3: Expand and maximize the quadratic equation

I = 1687.5 - 187.5x + 225x - 25x² = -25x² + 37.5x + 1687.5. This is a quadratic equation that opens downward, meaning it has a maximum point at its vertex.

The formula for the x-coordinate of the vertex of a parabola y = ax² + bx + c is -b/(2a). In this scenario, a = -25 and b = 37.5.

Step 4: Find the vertex

The x-coordinate of the vertex (maximum income) is -37.5 / (2 × -25) = 0.75. Therefore, the admission cost should be increased by $0.75 to maximize income.

User Bruno Habermann
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4 votes
I am not sure this wuestion
User Jeremy Kauffman
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