Question

What values of c and d make the equation true?

c = 2, d = 2
c = 2, d = 4
c = 6, d = 2
c = 6, d = 4

Answer 1

c= 6 and d=2 so the answer is C.

Answer 2

c=6 and d=2 makes the equation true

Explanation:

`\sqrt[3]{162x^cy^5} = 3x^2y(\sqrt[3]{6y^d})`

plug in c=2 and check

`\sqrt[3]{162x^2y^5}`

We cannot simplify cuberoot (x^2)

So c=2 does not works

Lets try with c=6 and d=2

`\sqrt[3]{162x^6y^5}`

Cuberoot(x^6) = x^2

cuberoot (y^5)= ycuberoot (y^2)

`\sqrt[3]{162x^6y^5} = 3x^2y(\sqrt[3]{6y^2})`

So c=6 and d=2 makes the equation true