Answer:
32.64%
Explanation:
Let's define the random variable X in the following way:
X: the volume of a soda in a quart soda bottle. We know that X is normally distributed with a mean of 32 ounces and a standard deviation of 1.2 ounces, i.e.,
= 32 ounces
= 1.2 ounces
The normal density function for a random variable with a mean of 32 and a standard deviation of 1.2 is given by
![f(x)=(1)/(√(2\pi )1.2) \exp[-((x-32)^(2) )/(2(1.2)^2) ]](https://img.qammunity.org/2018/formulas/mathematics/high-school/knn8g7ym8zly9s2ppw0w86hrjpps4xczfw.png)
and we need to calculate the following probability
, this probability is given by
= 0.3263552
you can use a computer to calculate this probability or a table from a book. You can use the following instruction in the R statistical programming language for example
pnorm(31.46, mean = 32, sd = 1.2) with give us 0.3263552, then,
the percentage we are looking for is (0.3263552)(100)=32.64.