Final answer:
To calculate the number of grams of HCl that can react with Al(OH)3, use the balanced chemical equation and stoichiometry. 0.470 g of Al(OH)3 reacts with approximately 1.32 g of HCl.
Step-by-step explanation:
To calculate the number of grams of HCl that can react with 0.470 g of Al(OH)3, we need to use the balanced chemical equation and stoichiometry. The balanced equation for the reaction between HCl and Al(OH)3 is:
6HCl + Al(OH)3 → 3H2O + AlCl3
From the equation, we can see that 6 moles of HCl react with 1 mole of Al(OH)3. To find the number of moles of HCl, we can use the molar mass of Al(OH)3 (78.0 g/mol) to convert the mass of Al(OH)3 to moles. Then, we can use the stoichiometry to calculate the number of moles of HCl. Finally, we can use the molar mass of HCl (36.46 g/mol) to convert moles of HCl to grams. Let's do the calculations:
- Calculate moles of Al(OH)3: 0.470 g / 78.0 g/mol = 0.00603 mol
- Calculate moles of HCl using stoichiometry: 0.00603 mol Al(OH)3 × (6 mol HCl / 1 mol Al(OH)3) = 0.0362 mol HCl
- Calculate grams of HCl: 0.0362 mol HCl × 36.46 g/mol = 1.32 g HCl
Therefore, the number of grams of HCl that can react with 0.470 g of Al(OH)3 is approximately 1.32 g of HCl.