Question

(6v^3+42v)/(2v^2+26v+84)

Answer 1

Answer:
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The simplied version is:
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"
`(3v(v^2+7))/((v^2+13v+42))` " ;

or; write as: "
`(3v(v^2+7))/((v+7)(v+6))` " .
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Step-by-step explanation:
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Given:
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"
`(6v^3 +42 v)/(2v^2 +26v + 84)` " ;
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→ Factor out a "6v"
`(6v(v^2+7))/(2(v^2+13v+42))` in the "numerator"; & factor out a "2" in the denominator; as follows:
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→
`(6v(v^2+7))/(2(v^2+13v+42))` ;
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→ "
`(3v(v^2+7))/((v^2+13v+42))` " ;
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or; factor out the "denominator" :
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→ (v² + 13v + 42) = (v+7)(v+6) ;
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and write as:
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→ "
`(3v(v^2+7))/((v+7)(v+6))` " .
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