Question

A stone is thrown straight up from the edge of a roof, 675 feet above the ground, at a speed of 16 feet per second. A. Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 3 seconds later?

Answer 1

The stone would be 579 feet high after 3 seconds.

Step-by-step explanation:

To calculate the height of the stone 3 seconds later, we can use the kinematic equation for position:

h = h0 + (v0 · t) + ((1/2) · a · t2)

where:

h is the final height

h0 = 675 feet is the initial height

v0 = 16 ft/s is the initial velocity

t = 3 seconds is the time

a = -32 ft/s2 is the acceleration due to gravity

Let's plug in the values and calculate:

h = 675 + (16 · 3) + ((1/2) · (-32) · 32)

Solving this equation, we get:

h = 675 + 48 - 144

h = 579 feet

Answer 2

627 ft. high after 3 seconds