Question

Solve for x over the complex numbers. x2+10x+41=0

Answer 1

x²+10x+41=0
using x=(-b±√b²-4ac)½
where a= 1
b=10
c=41

x= (-10±√10²-4×1×41)½
x=-5 ± √(100-164)
x=-5±√(-64)½
x=-5±4i
x=-5+4i or -5-4i
where i= √-1

Answer 2

The correct answer is X= -5±41