320,250 views
37 votes
37 votes
I have a number. I subtracted five from its half, multiplied the difference by four, and then addedeight. I have the original number. What is the original number?

User Dmcb
by
3.1k points

1 Answer

9 votes
9 votes

SOLUTION:

I have a number. Say


x

I subtracted five from its half, this would be;


(x)/(2)-5

multiplied the difference by four, thus;


4((x)/(2)-5)=2x-20

and then added eight, this is


2x-20+8=2x-12

I have the original number.


\begin{gathered} 2x-12=x \\ -12=-x \\ x=12 \end{gathered}

Thus, the original number is 12

User DanLebrero
by
2.3k points