Question

A town's population has been growing linearly. In 2003, the population was 25000, and the population has been growing by 1200 people each year.Write an equation for the population

x
years after 2003.

Answer 1

in year 2003 (starting year) it had 25000 pple
let's say a=25000
so steadily each year it increases by 1200
which means the difference between two consecutive years would be 1200 pple
now this is an arithmetic progression
using Tx=a+(x-1)1200
tx= 25000+(x-1)1200
tx=25000+1200x-1200
tx= 23800+1200x
that's the eqn after X years

Answer 2

y=25000*1200x

y would equal the population of the year and x is the amount of years passed.