Question

In rectangle PQRS, PQ = 18, PS = 14, and PR = 22.8. Diagonals PR and QS intersect at point T. What is the length of TQ ?

Answer 1

rectangle PQRS, PQ = 18, PS = 14, and PR = 22.8
so
Diagonals PR = QS
if PR = 22.8 then QS = 22.8

TQ = QS/2 = 22.8 / 2 = 11.4

anser
TQ = 11.4

Answer 2

TQ = 11.4

Explanation:

Given : In rectangle PQRS, PQ = 18, PS = 14, and PR = 22.8. Diagonals PR and QS intersect at point T.

To find : What is the length of TQ .

Solution : We have given rectangle PQRS

Side PQ = 18.

Side PS = 14.

Diagonal PR = 22.8 .

Properties of rectangle : (1) Opposite sides of rectangle are equals.

(2) Diagonals of rectangle are equal .

(3) Diagonals of rectangle bisect each other.

Then by second property :

Diagonal PR= QS .

QS = 22.8

By the Third property TQ =
`(1)/(2) * QS`.

TQ =
`(1)/(2) * 22.8`.

TQ = 11.4

Therefore, TQ = 11.4