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37 votes
Monochromatic light passes through two narrow slits 0.23 mm apart and forms an interference pattern on a screen 1.67 m away. If light of wavelength 671.37 nm is used, what is the distance from the center of the central maximum to the center of the third order bright fringe in centimeters?

User DanyialKhan
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1 Answer

17 votes
17 votes

Given:

• Distance between slits = 0.23 mm

,

• Distance, d = 1.67 m

,

• Wavelength = 671.37 nm

Let's find the distance from the center of the central maximum to the center of the third order bright fringe.

To find the distance, apply the formula:


y_m=(m\lambda L)/(d)

Where:

m = Third order = 3

λ is the wavelength = 67137 ncm

L = 1.67 m = 167 cm

d = 0.23 mm = 0.023 cm

Thus, we have:


\begin{gathered} y_3=(3*67137*10^(-9)*10^*167)/(0.023) \\ \\ y_3=(0.033635)/(0.23) \\ \\ y_3=1.46\text{ cm} \end{gathered}

Therefore, the distance is 1.46 centimeters.

ANSWER:

1.46 cm

User JSQuareD
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