• The balanced equation for the reaction is given by:
CH3CH2OH + O2 → CH3COOH+ H2O
• From the above reaction we can see that:
1 mole of ethanol (CH3Ch2OH) produces 1 mol of acetic acid(CH3COOH)
so . x mole of ethanol will produce 0.9mol of acetic acid ....(cross multiply)
xmol ethanol * 1mol acetic = 1mol ethamol* 0.9molacetic
∴ xmol ethanol = 1*0.9 /1
= 0.90 mol
• This means that, 0.90 mol of ethanol, is needed to produce 0.9mol acetic acid,.