Question

20 PTS

line segment jk and jl in the xy-coordinate both have a common endpoint j(-4,11) and midpoints an mv1(2,16) and mv2 (-3,5) respectively.

What is the distance between mv1 and mv2? round to the nearest tenth

Answer 1

We know that:


`MV_1=(2,16)\\\\MV_2=(-3,5)`

so the distance:


`d(MV_!,MV_2)=√((-3-2)^2+(5-16)^2)=√((-5)^2+(-11)^2)=\\\\=√(25+121)=√(146)\approx\boxed{12.1}`