Question

our boss asks you compare two sound waves and determine which has the higher frequency. Wave A has a period of 4⁄100 second and Wave B has a perio of 1⁄7 second.

Answer 1

Wave A- period = 4/100 and the frequency = 1/(4/100) = 100/4 = 25 Hz
Wave B- period = 1/7 and the frequency = 1/(1/7) = 7 Hz

Wave A has a higher frequency.

Answer 2

The periodic time is the inverse of frequency. This means that:
Period = 1/frequency
Therefore,
Frequency = 1/period

For wave A:
period = 4/100
frequency = 1/(4/100) = 100/4 = 25 Hz
For wave B:
period = 1/7
frequency = 1/(1/7) = 7 Hz

Based on this, wave A has higher frequency.