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The area of the base of a can is 45 square inches. Its height is 12 inches. If 1⁄3 of the height is cut off, what will be the volume of the can?

User Luntegg
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1 Answer

22 votes
22 votes

Answer:

The volume of the can will be of 360 cubic inches.

Explanation:

Volume of a can:

The volume of a can is:

V = Ab*h

In which Ab is the area of the base and h is the height.

In this question:

Area of the base is 45 square inches.

The height is 12 inches.

1/3 of the height will be cut off. 1/3 of the height is 12/3 = 4. 4 inches cut off, so the height is of 12 - 4 = 8 inches.

Volume of the can:

V = Ab*h = 45*8 = 360

The volume of the can will be of 360 cubic inches.

User Finslicer
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