Question

A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form? A=–n2 + 3n + 5 B=n2 + 6n + 1 C=2n2 + 6n – 1 D=3n2 + 5

Answer 1

B

Explanation:

Answer 2

A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form? We want (n)(2n+6) - (n^2-1). (Please note: n^2 is correct, while n2 is not.)

Multiplying out the first term: 2n^2 + 6n
Subtracting n^2-1: - (n^2 -1)
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n^2 + 6n + 1 (answer)