Question

Find the probability to generate a 3 digit even number without repetition from 1, 2, 3, 5.A.1/4B.1/2C.1D.0

Answer 1

Explanation

We can find the number of 3 digits as;

Last digit = 2 which implies one possibility

First digit = 1,3 or 5 which implies three possibilities

The second digit implies the remaining two possibilities.

Therefore, the total number of three-digit even numbers generated is;

`3*2*1=6\text{ }`

The total number of three-digit numbers is:

The first option is four possibilities

The second option is three possibilities

The third option is two possibilities

`4*3*2=24`

Therefore the probability is

`Pr(3\text{ digt even number) = }(6)/(24)=(1)/(4)`

Answer: Option A