Question

An electron is ejected horizontally at a speed of 1.5 ✕ 106 m/s from the electron gun of a computer monitor. if the viewing screen is 35 cm away from the end of the gun, how far will the electron travel in the vertical direction before hitting the screen?

Answer 1

The electron, ejected horizontally and not influenced by external forces such as gravity, magnetic, or electric fields, would have a vertical displacement of zero and thus would travel directly to the screen without any vertical deviation.

Step-by-step explanation:

An electron ejected horizontally with a speed of 1.5 × 106 m/s from an electron gun will continue to move in a straight line horizontally in the absence of any external forces. Since there is no mention of gravity, magnetic fields, or electric fields in the stated problem that could cause the electron to deviate from its path, the vertical displacement of the electron before hitting the screen would be zero if we disregard such forces. Hence, the electron will travel horizontally and hit the screen without any vertical displacement.

Answer 2

GivenHorizontal velocity, vxi = 1.5 *10^6 m/sDistance ,x =0.35 mFirst we will calculate the time takenx = vxi t0.35 m = (1.5 *10^6 m/s) tt =0.23 *10^-6 sThe vertical distance travelled by the electron isy =1/2 gt^2= 0.5 *9.8 m/s^2 *(0.23 *10^-6 s)^2= 0.25 *10^-12 m

Therefore, the answer is 0.25 *10^-12 m