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The sum of five consecutive numbers is -75. Which number is the least of these five numbers?

User Cfogelberg
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2 Answers

4 votes
SOLVING:
X + (X + 1) + (X + 2) + (X + 3) + (X + 4) = - 75
X + X + 1 + X + 2 + X + 3 + X + 4 = - 75
5X + 10 = - 75
5X = - 75 - 10
5X = - 85
X =

\frac{ \textbf{-85}}{ \textbf{5}}
X = - 17 ===> The first number.

- 17 + 1 = - 16 ===> The second number.
- 17 + 2 = - 15 ===> The third number.
- 17 + 3 = - 14 ===> The fourth number.
- 17 + 4 = - 13 ===> The fifth number.

TESTING:


-17-16-15-14-13=-75\\ \\\boxed{-75}=\boxed{-75}\quad\checkmark\ Correct.
GOOD LUCK...!!
User Picarus
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8.6k points
2 votes
Hello! I can help you with this! Do -75/5 to get -15. -15 will be your middle number. So for consecutive integers, -13 + -14 + -15 + -16 + -17 = 75. Those are five consecutive integers that have a sum of 75. The lowest of 5 integers is -17, because it’s the smallest of them all and the furthest to the left of the number line. A line further to the left of the number line means it’s smaller. Therefore, the rest of the five integers is -17.
User Tucker
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8.9k points

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