Question

A girl sits on a tire swing and is pushed in a circular motion by her father. Her tangential speed is 2.8 m/s and the girl travels in a circle with a diameter of 4.0 m. What is the girl's centripetal acceleration?

Answer 1

R = D/2 = 4.0 / 2 = 2 m

a = V² / R = 2,8² / 2 = 7.84 / 2 = 3.92 m/s²

Answer 2

`a_c = 3.92 m/s^2`

Step-by-step explanation:

tangential speed of the girl is given as

`v_t = 2.8 m/s`

diameter of the circle is given as

`d = 4.0 m`

so here the radius of the circle is given as

`R = 2.0 m`

now we know that centripetal acceleration of the object moving in circle is given as

`a_c = (v^2)/(R)`

`a_c = (2.8^2)/(2)`

`a_c = 3.92 m/s^2`