Question

What is the percent increase in tuition to the nearest tenth of a percent

Answer 1

a Percentage of increasing = [(New - Original)/original] x 100%

Since the original is 10500

Since the new is 11300

Then (New - original) = 11300 - 10500 = 800

Then substitute them in the rule above

`\begin{gathered} I=(800)/(10500)*100 \\ I=(8)/(105)*100 \\ I=7.62 \end{gathered}`

The increasing percentage is 7.62% to the nearest tenth of percent