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Solve for x: 32^x=4^(2x+1)

User Iashia
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x/32^x=4^(2x+1) We move all terms to the left: x/32^x-(4^(2x+1))=0 Domain of the equation: 32^x!=0 x!=0/1 x!=0 x∈R We multiply all the terms by the denominator x-((4^(2x+1)))*32^x=0
User Andrew Koper
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Hello There!

5x = 2(2x + 1)
5x = 4x +2
x = 2

Hope This Helps You!
Good Luck :)

- Hannah ❤
User Jeremy Caney
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