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A car moving at a speed of 8.0 meters per second enters a highway and accelerates at 3.0 meters per second^2. How fast will the car be moving after it has accelerated for 56 meters?

2 Answers

4 votes
20 meters per second. I use the formula V^2=V0^2 + 2*a*d. a is acceleration and d is distance.
User RandyTek
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4 votes

Answer:

Final speed of the car, v = 20 m/s

Step-by-step explanation:

It is given that,

Initial speed of the car, u = 8 m/s

Acceleration of the car,
a=3\ m/s^2

Let v is the speed of the car after it has accelerated for 56 meters. It can be calculated suing the third equation of motion. It is given by :


v^2-u^2=2ad


v^2=u^2+2ad


v^2=(8)^2+2* 3* 56

v = 20 m/s

So, the car is moving after it has accelerated for 56 meters is 20 m/s. Hence, this is the required solution.

User Rkosegi
by
8.3k points

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