Question

Raphael graphed the functions g(x) = x + 2 and f(x) = x – 1. How many units below the y-intercept of g(x) is the y-intercept of f(x)? The y-intercept of f(x) is units below the y-intercept of g(x).Raphael graphed the functions g(x) = x + 2 and f(x) = x – 1. How many units below the y-intercept of g(x) is the y-intercept of f(x)? The y-intercept of f(x) is units below the y-intercept of g(

Answer 1

For the first question, the y-intercept of f(x) is 3 units below the y-intercept of g(x). For the second question, the y-intercept of f(x) is 3 units above the y-intercept of g(x).

Answer 2

The y-intercept of f(x) is 3 units below the y-intercept of g(x).

Explanation:

We are given,

The functions
`f(x)=x-1` and
`g(x)=x+2`.

Now, y-intercept is the point where the graph of the function crosses y-axis.

So, y-intercept is obtained when x= 0.

Substituting x= 0 in the functions, we get,

`f(0)=0-1\\f(0)=-1` and
`g(0)=0+2\\g(0)=2`.

Thus, we get that,

The y-intercept of the the function f(x) is -1.

The y-intercept of the function g(x) is at 2.

Thus, the y-intercept of f(x) is 2-(-1)= 3 units below the y-intercept of g(x) as seen below.