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Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) f(x) = x^3 − x^2 − 12x + 3,    [0, 4]

User Loonatick
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well, is the function continuous? yes, is a cubic one, you can graph it if you wish, is continuous all the way, and of course at [ 0, 4] too.

is it differentiable? you can always look at the graph between 0,4 and is a smooth transition line, thus yes, it is differentiable, but let's check anyway,


\bf \cfrac{dy}{dx}=3x^2-2x-12 its derivative has no asymptotes and therefore no "cusps", so yes, is differentiable all around.

is f(0) = f(4), let's check

f(0) = 0+0+0+3, f(0) = 3
f(4) = 64 - 16 - 48 + 3, f(4) = 3

yeap

there must then be a "c" value(s) with a horizontal tangent slope, let's check, is really just the critical points.


\bf \cfrac{dy}{dx}=3x^2-2x-12\implies 0=3x^2-2x-12 \\\\\\ \textit{using the quadratic formula} \\\\\\ x=\cfrac{-(-2)\pm√((-2)^2-4(3)(-12))}{2(3)}\implies x=\cfrac{2\pm√(4+144)}{6} \\\\\\ x=\cfrac{2\pm 2√(37)}{6}\implies x=\cfrac{2\pm√(37)}{3}\impliedby \textit{c's}
User Roman Gudkov
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