Question

A student has two substances at a lab table. One substance is iron pyrite (fool's gold) and the other is real gold. After placing a 20.0-gram sample of iron pyrite into 40.0 mL of water in a graduated cylinder, it displaces 4.0 mL of water. The density of real gold is almost 4 times larger than iron pyrite. If a 20.0-gram sample of real gold is placed into the same amount of water, approximately how much water will be displaced?

A) 1 mL
B) 4 mL
C) 16 mL
D) 20 mL

Answer 1

The answer is A) 1 mL 

Answer 2

Answer:The correct answer is option A.

Step-by-step explanation

Mass of the iron pyrite= 20 grams

Volume water displaced by the iron pyrite = 4 mL

Density of iron pyrite=
`d_i=(Mass)/(Volume)=(20 g)/(4 mL)=5 g/mL`

`d_g=4* d_i`(Given)

`d_g=4* 5 g/mL=20 g/mL`

Mass of gold = 20 g

Volume of water displaced by the 20 grams of water = V

`D_g=20 g/mL=(20 g)/(V)`

V = 1 mL

20 grams of gold will displace 1 ml of water.So, the correct answer is option A.