Question

Pascal wants to find the sum of the measures of the interior angles of a polygon that has n sides. How could he do this?

Answer 1

anwser c.
multiply by 180 (n-2)



count how many sides you have.. subtract the sides by the number 2. then multiply tht by 180

Answer 2

Answer with explanation:

Smallest Polygon = Triangle , which has 3 sides

Sum of angles of triangle = 180°→→, Using the angle sum property of triangle.

We can find the Sum of angles of triangle, using the formula

= (n-2)×180°

= (3-2)×180°

= 1 × 180°

= 180°

A Quadrilateral has four sides.

Sum of angles of Quadrilateral = 360°

Or , using the formula

=(4-2)×180°

=2 × 180°

=360°

For, n sided Polygon

Sum of it's Interior angles = (n-2) × 180°

To prove this, we should divide that polygon into triangles, and multiply number of triangles by angle of 180°.

For, example, Quadrilateral can be divided into two triangles , sum of interior angles of Quadrilateral =2 × 180°=360°