Question

The density of gold is 19.3 g/cm3. A piece of gold displaces 2 mL of water. The specific gravity of gold is:

A.19.3
B.38.6
C.9.6
D.0.10

Answer 1

The answer to this is 19.3

Answer 2

A) 19.3

Step-by-step explanation:

As we know that specific gravity is defined as the ratio of weight of the object and weight of the water displaced by the object

so it is given by

`Specific \gravity = (weight \: of \: object)/(weight \: of \: water\: displaced)`

now we have

weight of the object = (density)(volume)g

weight of object =
`(19.3 g/cm^3)(2 mL)g`

now weight of the liquid displaced is given by

weight of water displaced =
`(1 g/cm^3)(2 mL)g`

now we have

specific gravity =
`((19.3)(2mL)g)/((1)(2 mL)g)`

specific gravity = 19.3