Question

If 31.25

10
18
electrons are removed from a
neutral dielectric, how much charge is stored in
coulombs?

Answer 1

1 C = 6.24150965(16)×10^18 electrons

31.25 x 10^18 electrons / (6.24150965(16)×10^18 electrons / C) = 5.007 Coulombs

I hope this helps.

Answer 2

it will become charged by Q = 5C

Step-by-step explanation:

When electron is removed from matter then the system will get positively charged

So we will have

`Q = Ne`

here N = number of electrons that is removed

`N = 31.25 * 10^(18)`

also we know that charge on one electron is given as

`e = 1.6 * 10^(-19)`

here we have

`Q = Ne`

`Q = (31.25 * 10^(18))(1.6 * 10^(-19))`

`Q = 5 C`

so it will become charged by Q = 5C