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What is the percent by mass of water in Na2SO4 • 10H2O?

Use mc003-1.jpg.
5.59%
11.26%
44.08%
55.92%

User AlgoRythm
by
7.7k points

2 Answers

6 votes

The answer is 55.92%

User Littlebenlittle
by
8.1k points
3 votes

Answer : The correct option is, 55.92 %

Solution : Given,

Molar mass of
Na_2SO_4.10H_2O = 322 g/mole

Molar mass of water = 18 g/mole

The mass of
10H_2O =
10* 18=180g

Now we have to calculate the percent by mass of water in
Na_2SO_4.10H_2O

Formula used :


\text{Percent by mass of water}=\frac{\text{Mass of}10H_2O}{\text{Mass of }Na_2SO_4.10H_2O}* 100=(180g)/(322g)* 100=55.92\%

Therefore, the percent by mass of water in
Na_2SO_4.10H_2O is, 55.92 %

User Matthew Taylor
by
8.0k points