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27 votes
*equasion attached*1. The graph opens A. Up B. Down 2. The vertex of the graph is A. (2,5)B(-2,-5)C.(-2,5)3. The axis of symmetry of the graph is A. X=2B. X=-2

*equasion attached*1. The graph opens A. Up B. Down 2. The vertex of the graph is-example-1
User Jannis
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1 Answer

8 votes
8 votes

We are given the following function:


y=-(1)/(3)(x+2)^2+5

This is a function of the form:


y=a(x-h)^2+k

We have that:


a=-(1)/(3)

Since the value of "a" is negative this means that the graph opens down.

The vertex of the graph is the point:


V=(h,k)

Therefore, the vertex of the function is:


(h,k)=(-2,5)

The axis of symmetry of the graph is the x-coordinate of the vertex. Therefore, the axis of symmetry is:


x=-2

The graph of the function looks like this:

*equasion attached*1. The graph opens A. Up B. Down 2. The vertex of the graph is-example-1
User Relekang
by
2.7k points