Question

Please draw/show the phase change graph!!! I know the energy just need to figure out how to do the graph!!

Answer 1

Given:

Initial temperature of ice,

`T_i=-25^(\circ)C`

Mass of ice,

`\begin{gathered} m=15\text{ g} \\ =0.015\text{ kg} \end{gathered}`

Final temperature,

`T_F=55^(\circ)C`

The heat absorbed to bring the temperature of ice to 0°C is given as,

`Q_1=mC_i(0^(\circ)C-T_i)^{}`

Here, C_i is the specific heat of ice.

Substituting all known values,

`\begin{gathered} Q_1=0.015*2093*(0^(\circ)C-(-25^(\circ)C)) \\ =784.875\text{ J} \end{gathered}`

The heat absorbed to melt ice is given as,

`Q_2=mL`

Here, L is latent heat of fusion of ice.

Substituting all known values,

`\begin{gathered} Q_2=0.015*33600 \\ =504\text{ J} \end{gathered}`

The heat absorbed by water to raise its temperature to 55°C is given as,

`Q_3=mC_w(T_F-0^(\circ)C)`

Here, C_w is the specific heat of water.

Substituting all known values,

`\begin{gathered} Q_3=0.015*4200*(55^(\circ)C-0^(\circ)C) \\ =3465\text{ J} \end{gathered}`

Therefore, the heat absorbed the ice to raise the temperature for -25° C to 55°C is ,

`Q=Q_1+Q_2+Q_3`

Substituting all known values,

`\begin{gathered} Q=784.875+504+3465 \\ =4753.875\text{ J} \end{gathered}`

Therefore, the the heat absorbed the ice to raise the temperature for -25° C to 55°C is 4753.875 J.

Phase change diagram: