Question

Two jets leave an air base at the same time and travel in opposite directions. one jet travels through 65 mi/h slower than the other. If the two jets are 8934 miles apart after 6 hours, what is the rate of each jet?Rate of the slower jet:__mi/hrate of the faster jet:____mi /h

Answer 1

One jet travels through 65 mi/h slower than the other

Jet one x (rate)

Jet two x + 65 mi/h (rate)

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Rate= mi/h

time = h

Rate * time = (mi/ h)*h = mi

rate jate 1 * time + rate jate 2 * time = 8934

(x + 65 )* 6 + (x)*6 = 8934

6x + 6*65 + 6x = 8934

12x = 8934 - 6*65

12x = 8934- 390

x = 8544/12

x= 712

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Answer

The slower 712 mi/h

The faster 712+ 65 = 777

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