Question

Write a translation rule that maps point D(7,-3) onto point D'(2,5).

Answer 1

ANSWER

The translation rule is


`D(x,y)\rightarrow D'(x-5,y+8).`

Step-by-step explanation

Let
`\binom{x}{y}`
be the translation vector that maps
`D(7,-3)`
on to
`D'(2,5)`.

Then we have the vector equation,


`\binom{7}{ - 3} + \binom{x}{y} = \binom{2}{5}`

We now solve for

`\binom{x}{y}`


`\binom{x}{y} = \binom{2}{5} - \binom{7}{ - 3}`

This simplifies to,


`\binom{x}{y} = \binom{2 - 7}{5 - - 3}`


`\binom{x}{y} = \binom{2 - 7}{5 + 3}`


`\binom{x}{y} = \binom{ - 5}{8}`

Therefore the translation rule is,


`D(x,y)\rightarrow D'(x-5,y+8)`

Answer 2

We are given D (7, -3) and D'(2, 5).

SAppy the transformation
D'(x,y) → D(x-5, y+8).
Then
x=7 → x=7-5 = 2
y=-3 → y=-3+8 = 5

Answer: D (x-5, y+8) → D'