Question

If there are 10.0 g of sucrose and 8.0 g of oxygen, how many moles of sucrose are available for this reaction? A.) 0.029 mol B.) 0.250 mol C.) 0.351 mol D.) 3.00 mol

Answer 1

0.029 iss the answer. 

Answer 2

Answer: A.) 0.029

Explanation: To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}`

For sodium:

Mass of sucrose given = 10 g

Molar mass of sucrose
`C_(12)H_(22)O_(11)` = 342 g/mol

Putting values in above equation, we get:

`\text{Moles of sodium}=(10g)/(342g/mol)=0.029mol`

Thus the number of moles of sucrose available for this reaction will be 0.029.