Question

Please help me Open up or down, Vertex: (5,2), passes through: (6,3)

Answer 1

For this case the general equation of a parabola is given by:

`y-k=a(x-h)^2`

And for this case the vertex is given by:

V= (h= 5, k= 2)

Then replacing we got:

`y-2=a(x-5)^2`

We can use the point given x=6 and y=3 and replacing we got:

`3-2=a(6-5)^2`

And we got a= 1

Then the equation would be:

`y=(x-5)^2+2`