Question

The width of a rectangle is 8 inches shorter than its length. The perimeter of the rectangle is 18 square cm. What are the length and width? Which equation models this problem?

A. 8 x L = 18 - 8
B. L(L - 8) = 18
C. L + (8 + 2L) = 18
D. 2L + 2 (L - 8) = 18

Answer 1

answer:
D. 2L+2(L-8) = 18

Answer 2

Option D. 2[L + ( L-8)] = 18

Explanation:

Let the length of rectangle is L and width is W

The width of a rectangle is 8 meters shorter than its length

Then equation will be W = L - 8 -----------(1)

The perimeter of the rectangle is 18 cm

Then P = 18 cm = 2 ( l + w )

2(l + w) = 18 ----------(2)

Now we substitute the value of W from equation (1) to equation (2)

2[L + ( L-8)] = 18

Option D. is the answer.