Question

If f (x)=2x^2+1 and g (x)=3x-2 what is the value of f (g (-2))?

Answer 1

`\bf \begin{cases} f(x)=2x^2+1\\ g(x)=3x-2\\ \end{cases}\qquad g(-2)=3(-2)-2\implies \boxed{g(-2)=-8} \\\\\\ f(~~g(-2)~~)\implies f\left( \boxed{-8} \right)\implies f(-8)=2(-8)^2+1 \\\\\\ f(-8)=2(64)+1\implies f(-8)=129`