Question

The following table shows the breakdown of opinions for both faculty and students in a recent survey about the new restructuring of the campus to include an honors college. find the probability that a randomly selected person is either in favor of or opposed to the restructuring. express your answer as a fraction.

Answer 1

Given:

The number of people are in the favor of restructuring is 50.

The number of people are in the oppose of restructuring is 82 .

The total number of persons is 182.

The probability of persons is in the favor of restructuring is,

`\begin{gathered} \text{Probability}=\frac{Desired\text{ outcomes}}{t\text{otal outcomes}} \\ P_F=(50)/(182) \end{gathered}`

The probability of persons is in the oppose of restructuring is,

`P_O=(82)/(182)`

To find the probability that a randomly selected person is either in favor of or opposed to the restructuring,

`\begin{gathered} P(\text{Favor or oppose)=}P_F+P_O \\ =(50)/(182)+(82)/(182) \\ =(50+82)/(182) \\ =(132)/(182) \\ =\: (66)/(91) \end{gathered}`

Answer:

`P=(66)/(91)`