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The point (2, 4) is on the graph of f(x) = x^2. What is the value of b if the point (0.5, 4) is on the graph of f(bx)?

4
0.5
1
2.5

2 Answers

4 votes

Answer:

A. 4

Explanation:

User Joaerl
by
7.8k points
5 votes
We know that (0.5, 4) is not on the graph of x^2 because when x = 0.5, f(x) = 0.25.
Since our function is now f(bx), and we know that x = 0.5, then we need to multiply 0.5 by something so that (b * 0.5)^2 = 4
We can now solve for b
(b * 0.5)^2 = 4
take the square root of both sides of the equal sign
√(b * 0.5)^2 = √4
b * 0.5 = 2
divide both sides of the equal sign by 0.5
b * 0.5 / 0.5 = 2/0.5
b = 4

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User Roman Gherta
by
8.9k points

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