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Find the loci for the complex numbers that satisfy
|z-1|=|z+1|

1 Answer

2 votes
Let
z=x+iy. Then


|z-1|=√((x-1)^2+y^2)

|z+1|=√((x+1)^2+y^2)

\implies (x-1)^2+y^2=(x+1)^2+y^2

\implies (x-1)^2=(x+1)^2

\implies -2x=2x

\implies x=0
User Serkant Karaca
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