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44 votes
Charlene is wrapping the box below. How much wrapping paper will she need to wrap the box with no overlap? 12 in. 3 in. 10 in.a. 186 in b. 372 in c. 480 in d. 558 in

User Arttu Peltonen
by
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1 Answer

17 votes
17 votes

Step 1: Write out the formula


\text{TSA = }2(lw+lh+hw)
\begin{gathered} \text{where} \\ \text{TSA = the total surface area of the box} \\ l=\text{ the length of the box} \\ w=\text{ the width of the box} \\ h=\text{ the height of the box} \end{gathered}

Step 2: Write out the given values and substitute them into the formula


\begin{gathered} l=12in \\ w=3in \\ h=10in \end{gathered}

Therefore,


\text{TSA = 2(12}*3+12*10+10*3)=2(36+120+30)=2*186=372in^2

The quantity of wrapping needed is the total surface area of the box.

Therefore, the quantity of wrapping needed is 372 square inches. Choice B

User Calloway
by
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