Question

Calculate the water pressure at the bottom of the100-m-high water tower shown in the photo that opens this chapter.

Answer 1

Given data

*The given height is h = 100 m

*The given density of the water is D_w = 1000 kg.m^3

*The value of the acceleration due to gravity is g = 9.8 m/s^2

The formula for the water pressure at the bottom of the tank is given as

`P=D_wgh`

Substitute the known values in the above expression as

`\begin{gathered} P=(1000)(9.8)(100) \\ =9.8*10^5\text{ Pa} \end{gathered}`

Hence, the water pressure at the bottom of the tank is P = 9.8 × 10^5 Pa