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During the World Series the host city wide hotel occupancy rose 21% over the prior busiest night. If the busiest night had been 76% occupany, what was the new record? (use % symbol in answer)

User Yosep Kim
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2 Answers

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The busiest night had occupancy of 76%

During the World Series, the occupancy increased by 21% to a new record.
The new record is
76% + (76%)*0.21 = 76%*1.21 = 91.96%

Answer: 91.96%
User Scott Conway
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1 vote

Answer:

91.96%.

Explanation:

We have been given that during the World Series the host city wide hotel occupancy rose 21% over the prior busiest night. The busiest night had been 76% occupancy.


\text{New record}=\text{Old record+ Increase in old record}

To find the new record of occupancy, we will find 21% of 76% and add it to 76%.


\text{The new record}=76\%+({21\%\text{ of } 76\%)


\text{The new record}=(76)/(100)+({(21)/(100)*(76)/(100))


\text{The new record}=0.76+({0.21* 0.76)


\text{The new record}=0.76+0.1596


\text{The new record}=0.9196

Now let us convert our answer in percentage by multiplying our answer by 100.


\text{The new record}=0.9196* 100=91.96\%

Therefore, the new record of occupancy was 91.96%.

User Veggerby
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