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Find the general solution of the given differential equation. x2y' + x(x + 2)y = ex

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x^2y'+x(x+2)y=e^x

x^2e^xy'+x(x+2)e^xy=e^(2x)

\bigg(x^2e^xy\bigg)'=e^(2x)

x^2e^xy=\frac{e^(2x)}2+C

y=(e^x)/(2x^2)+\frac C{x^2e^x}
User Alex Lau
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